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X^2=12X+30
We move all terms to the left:
X^2-(12X+30)=0
We get rid of parentheses
X^2-12X-30=0
a = 1; b = -12; c = -30;
Δ = b2-4ac
Δ = -122-4·1·(-30)
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{66}}{2*1}=\frac{12-2\sqrt{66}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{66}}{2*1}=\frac{12+2\sqrt{66}}{2} $
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